/** *@file knowledge.c *\brief Procedures concerning knowledge structures. * * The main issue of this code is to maintain the minimal property of the knowledge set. */ #include #include #include "termlist.h" #include "knowledge.h" #include "memory.h" #include "system.h" #include "debug.h" /* * Knowledge stuff * * Note that a really weird thing is going on involving unpropagated substitutions. * Idea: * * 1. Substitute terms by filling in ->subst. * Now, either: * 2a. Undo this by knowledgeUndo. * 2b. Propagate it, modifying the knowledge beyond repair by knowledgeSubstDo. Now inKnowledge works again. * 2c. inKnowledge/knowledgeSet if something is in the knowledge: this does not consider the substitutions!, and * they now have some overhead. */ //! Open knowledge code. void knowledgeInit (void) { return; } //! Close knowledge code. void knowledgeDone (void) { } //! Allocate a fresh memory block the size of a knowledge struct. /** * Memory will not be initialized. *@return Pointer to a fresh memory block. */ Knowledge makeKnowledge () { return (Knowledge) memAlloc (sizeof (struct knowledge)); } //! Create a new empty knowledge structure. /** *@return Pointer to an empty knowledge structure. */ Knowledge emptyKnowledge () { Knowledge know; know = makeKnowledge (); know->basic = NULL; know->encrypt = NULL; know->inverses = NULL; know->vars = NULL; return know; } //! Duplicate a knowledge structure. /** * Makes copies using termlistShallow() of knowledge::basic, knowledge::encrypt and * knowledge::vars. * For the inverses, only the pointer is copied. *@param know The knowledge structure to be copied. *@return A pointer to a new memory struct. *\sa termlistShallow(), knowledgeDelete() */ Knowledge knowledgeDuplicate (Knowledge know) { Knowledge newknow; if (know == NULL) { warning ("Trying to copy empty knowledge."); return NULL; } newknow = makeKnowledge (); newknow->basic = termlistShallow (know->basic); newknow->encrypt = termlistShallow (know->encrypt); newknow->vars = termlistShallow (know->vars); newknow->inverses = know->inverses; return newknow; } //! Delete a knowledge set. /** * Typically used to destroy something made with knowledgeDuplicate(). *\sa knowledgeDuplicate() */ void knowledgeDelete (Knowledge know) { if (know != NULL) { termlistDelete (know->basic); termlistDelete (know->encrypt); termlistDelete (know->vars); memFree (know, sizeof (struct knowledge)); } } //! Destroy a knowledge set. /** * Unlike knowledgeDelete(), uses termlistDestroy() to remove knowledge::basic, * knowledge::encrypt and knowledge::vars substructures. *\sa knowledgeDelete() */ void knowledgeDestroy (Knowledge know) { if (know != NULL) { termlistDestroy (know->basic); termlistDestroy (know->encrypt); termlistDestroy (know->vars); // termlistDestroy(know->inverses); memFree (know, sizeof (struct knowledge)); } } //! Add a term to a knowledge set. /** *@param know The knowledge set. *@param term The term to be added. *@return True iff the term was actually new, and added. */ int knowledgeAddTerm (Knowledge know, Term term) { if (know == NULL) { warning ("Trying to add term to uninitialised (NULL) Know pointer."); return 1; } if (term == NULL) return 0; term = deVar (term); /* for tuples, simply recurse for components */ if (isTermTuple (term)) { int status; status = knowledgeAddTerm (know, TermOp1 (term)); return knowledgeAddTerm (know, TermOp2 (term)) || status; } /* test whether we knew it before */ if (inKnowledge (know, term)) return 0; /* adding variables? */ know->vars = termlistAddVariables (know->vars, term); knowledgeSimplify (know, term); if (isTermLeaf (term)) { know->basic = termlistAdd (know->basic, term); } if (term->type == ENCRYPT) { Term invkey = inverseKey (know->inverses, TermKey (term)); if (inKnowledge (know, invkey)) { /* we can decrypt it */ knowledgeAddTerm (know, TermOp (term)); if (!inKnowledge (know, TermKey (term))) { /* we know the op now, but not the key, so add it anyway */ know->encrypt = termlistAdd (know->encrypt, term); } } else { /* we cannot decrypt it, and from the initial test we know we could not construct it */ know->encrypt = termlistAdd (know->encrypt, term); } termDelete (invkey); } return 1; } //! Try to simplify knowledge based on a term. /** *@param know A knowledge set. *@param key A key, i.e. it can decrypt anything that was encrypted with term^{-1}. */ void knowledgeSimplify (Knowledge know, Term key) { Termlist tldecrypts = NULL; Termlist scan = know->encrypt; Term invkey = inverseKey (know->inverses, key); while (scan != NULL) { if (isTermEqual (TermKey (scan->term), invkey)) { tldecrypts = termlistAdd (tldecrypts, TermOp (scan->term)); know->encrypt = termlistDelTerm (scan); scan = know->encrypt; } else scan = scan->next; } termDelete (invkey); knowledgeAddTermlist (know, tldecrypts); termlistDelete (tldecrypts); } //! Add a termlist to the knowledge. /* *@return True iff there was at least one new item. *\sa knowledgeAddTerm() */ int knowledgeAddTermlist (Knowledge know, Termlist tl) { int flag = 0; while (tl != NULL) { flag = knowledgeAddTerm (know, tl->term) || flag; tl = tl->next; } return flag; } //! Add an inverse pair to the knowledge void knowledgeAddInverse (Knowledge know, Term t1, Term t2) { know->inverses = termlistAdd (know->inverses, t1); know->inverses = termlistAdd (know->inverses, t2); return; } //! Set an inverse pair list for the knowledge. /** * List pointer is simply copied, so don't delete it later! */ void knowledgeSetInverses (Knowledge know, Termlist tl) { know->inverses = tl; } //! Is a term a part of the knowledge? /** *@param know The knowledge set. *@param term The term to be inferred. *@return True iff the term can be inferred from the knowledge set. */ int inKnowledge (const Knowledge know, Term term) { mindwipe (know, inKnowledge (know, term)); /* if there is no term, then it's okay 'fur sure' */ if (term == NULL) return 1; /* if there is a term, but no knowledge, we're in trouble */ if (know == NULL) return 0; term = deVar (term); if (isTermLeaf (term)) { return inTermlist (know->basic, term); } if (term->type == ENCRYPT) { return inTermlist (know->encrypt, term) || (inKnowledge (know, TermKey (term)) && inKnowledge (know, TermOp (term))); } if (term->type == TUPLE) { return (inTermlist (know->encrypt, term) || (inKnowledge (know, TermOp1 (term)) && inKnowledge (know, TermOp2 (term)))); } return 0; /* unrecognized term type, weird */ } //! Compare two knowledge sets. /** * This does not check currently for equivalence of inverse sets, which it should. *@return True iff both knowledge sets are equal. */ int isKnowledgeEqual (Knowledge know1, Knowledge know2) { if (know1 == NULL || know2 == NULL) { if (know1 == NULL && know2 == NULL) return 1; else return 0; } if (!isTermlistEqual (know1->encrypt, know2->encrypt)) return 0; return isTermlistEqual (know1->basic, know2->basic); } //! Print a knowledge set. void knowledgePrint (Knowledge know) { indent (); if (know == NULL) { eprintf ("Empty.\n"); return; } eprintf (" [Basic]: "); termlistPrint (know->basic); eprintf ("\n"); indent (); eprintf (" [Encrp]: "); termlistPrint (know->encrypt); eprintf ("\n"); indent (); eprintf (" [Vars]: "); termlistPrint (know->vars); eprintf ("\n"); } //! Print a knowledge set, short version (no newline) void knowledgePrintShort (const Knowledge know) { indent (); if (know == NULL) { eprintf ("Empty"); return; } if (know->basic != NULL) { termlistPrint (know->basic); if (know->encrypt != NULL); { eprintf (", "); } } if (know->encrypt != NULL) { termlistPrint (know->encrypt); } } //! Print the inverses list of a knowledge set. void knowledgeInversesPrint (Knowledge know) { Termlist tl; int after = 0; if (know == NULL) { eprintf ("Empty knowledge."); return; } tl = knowledgeGetInverses (know); if (tl == NULL) { eprintf ("None."); } else { while (tl != NULL && tl->next != NULL) { if (after) { eprintf (","); } eprintf ("("); termPrint (tl->term); eprintf (","); termPrint (tl->next->term); eprintf (")"); after = 1; tl = tl->next->next; } } } //! Yield the set of representatives for the knowledge. /** * Note: this is a shallow copy, and needs to be termlistDelete'd. *\sa termlistDelete() */ Termlist knowledgeSet (const Knowledge know) { Termlist tl1, tl2; tl1 = termlistShallow (know->basic); tl2 = termlistShallow (know->encrypt); return termlistConcat (tl1, tl2); } //! Get the inverses pointer of the knowledge. /** * Essentially the inverse function of knowledgeSetInverses() */ Termlist knowledgeGetInverses (const Knowledge know) { if (know == NULL) return NULL; else return know->inverses; } //! Get all basic elements in the knowledge /** * This function is used by match_basic, to determine all basic elements in the knowledge set. * Most of the time this doesn't even change, so it might become a parameter of knowledge. * For now, this will have to do. * *@todo Investigate whether the basics in the knowledge set should be a parameter of knowledge, as it doesn't change very often. */ __inline__ Termlist knowledgeGetBasics (const Knowledge know) { return termlistAddBasics (termlistAddBasics (NULL, know->basic), know->encrypt); } //! check whether any substitutions where made in a knowledge set. /** * Typically, when a substitution is made, a knowledge set has to be reconstructed. * This procedure detects this by checking knowledge::vars. *@return True iff an open variable was later closed by a substitution. *\sa knowledgeReconstruction() */ int knowledgeSubstNeeded (const Knowledge know) { Termlist tl; if (know == NULL) return 0; tl = know->vars; while (tl != NULL) { if (tl->term->subst != NULL) return 1; tl = tl->next; } return 0; } //! Reconstruct a knowledge set. /** * This is useful after e.g. substitutions. * Just rebuilds the knowledge in a new (shallow) copy. *@return The pointer to the new knowledge. *\sa knowledgeSubstNeeded() */ Knowledge knowledgeReconstruction (const Knowledge know) { Knowledge newknow = emptyKnowledge (); newknow->inverses = know->inverses; knowledgeAddTermlist (newknow, know->basic); knowledgeAddTermlist (newknow, know->encrypt); return newknow; } //! Propagate any substitutions just made. /** * This usually involves reconstruction of the complete knowledge, which is * 'cheaper' than a thorough analysis, so we always make a copy. *\sa knowledgeReconstruction() */ Knowledge knowledgeSubstDo (const Knowledge know) { /* otherwise a copy (for deletion) is returned. */ return knowledgeReconstruction (know); } //! Undo substitutions that were not propagated yet. /** * Undo the substitutions just made. Note that this does not work anymore after knowledgeSubstDo() */ void knowledgeSubstUndo (const Knowledge know) { Termlist tl; tl = know->vars; while (tl != NULL) { tl->term->subst = NULL; tl = tl->next; } } //! Yield the minimal set of terms that are in some knowledge, but not in some other set. /** * Yield a termlist (or NULL) that represents the reduced items that are * in the new set, but not in the old one. *@param oldk The old knowledge. *@param newk The new knowledge, possibly with new terms. *@return A termlist of miminal terms in newk, but not in oldk. */ Termlist knowledgeNew (const Knowledge oldk, const Knowledge newk) { Termlist newtl; void addNewStuff (Termlist tl) { while (tl != NULL) { if (!inKnowledge (oldk, tl->term)) { newtl = termlistAdd (newtl, tl->term); } tl = tl->next; } } newtl = NULL; addNewStuff (newk->basic); addNewStuff (newk->encrypt); return newtl; }