fix spelling
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Andre Henriques 2023-11-07 22:07:33 +00:00
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@ -146,7 +146,7 @@
\subsection*{4.3}
Our random value is $R = u-bit long digit$ which means that it has $2^u$ possible values.
And since we know that $q$ balls into $p$ holes a colision is bound to happend at the probability of $\frap{q^2}{2p}$ we can calculate:
And since we know that $q$ balls into $p$ holes a colision is bound to happend at the probability of $\frac{q^2}{2p}$ we can calculate:
$$\frac{q^2}{2(2^u)}\gt\frac{1}{2}\iff q\gt 2^{\frac{u}{2}}$$
\subsection*{4.4}