From f132feca53461d235aed6c5947b906f58ba9a80f Mon Sep 17 00:00:00 2001
From: Andre Henriques <andr3h3nriqu3s@gmail.com>
Date: Fri, 3 Nov 2023 13:00:42 +0000
Subject: [PATCH] Fix xor

---
 cw/cw.tex | 4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

diff --git a/cw/cw.tex b/cw/cw.tex
index d3042f4..05bfc69 100644
--- a/cw/cw.tex
+++ b/cw/cw.tex
@@ -53,8 +53,8 @@
 	if the message is only one block long:
 	$$H=E$$
 	$$m\ne m'$$
-	$$H(m)=E(K, IV \xor m) = C_1$$
-	$$H(m')=E(K, IV \xor m') = C_2$$
+	$$H(m)=E(K, IV \oplus m) = C_1$$
+	$$H(m')=E(K, IV \oplus m') = C_2$$
 	And if there the hashing function was not collision resistant that would imply
 	$$C_1=C_2\implies D(C_1)=D(C_2) \impies m=m'$$
 	and since $m !=m'$ the hash function is collision resistant, for messages with 1 block.