done 3

cw/cw.tex

@@ -119,7 +119,7 @@
 	I used the openssl crypto libaray with the $p,q,d,m,e$ to decrypt the cipher text
 	\subsection*{3.4}
 	While factorizing the numbers takes more time, then a dictionary attack, it allows me to decrypting any message that was encrypted with this public key. It also allows me to decrypt messages that have diferent padding including padding methods that use random values.
-	\subsction*{3.5}
+	\subsection*{3.5}
 	Yes, since I know the private key I can just decrypt the message.
 
 	\section*{5}