diff --git a/cw/cw.tex b/cw/cw.tex
index 2fd1f92..36e44c2 100644
--- a/cw/cw.tex
+++ b/cw/cw.tex
@@ -147,14 +147,14 @@
 	\subsection*{4.3}
 	Our random value is  $R = u-bit long digit$ which means that it has $2^u$ possible values.
 	And since we know that $q$ balls into $p$ holes a colision is bound to happend at the probability of $\frac{q^2}{2p}$ we can calculate:
-	$$\frac{q^2}{2(2^u)}\gt\frac{1}{2}\iff q\gt 2^{\frac{u}{2}}$$
+	$$\frac{q^2}{2(2^u)}>\frac{1}{2}\iff q> 2^{\frac{u}{2}}$$
 
 	\subsection*{4.4}
 	The size of TripleDES is 64 bit long which makes $u=64/2=32$ making the q
-	$q\gt 2^\frac{32}{2}\iff q \gt 65536$
+	$q> 2^\frac{32}{2}\iff q > 65536$
 	\subsection*{4.5}
 	The size of AES is 128 bit long which makes $u=128/2=64$ making the q
-	$q\gt 2^\frac{64}{2}\iff q \gt 4294967296$
+	$q>t 2^\frac{64}{2}\iff q > 4294967296$
 	\subsection*{4.6}
 	Since in in both 4.4 and 4.5 the value of $q$ is not large enough the scheme is not CPA secure